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Question

The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and 426 S cm(2) mol1 respectively. The molar conductivity at infinite dilution of barium sulphate isS cm2 mol1. (Round off to the Nearest Integer)

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Solution

Λ(BaCl2)=280 S cm2 mol1

Λ(H2SO4)=860 S cm2mol1

Λ(HCl)=426 S cm2mol1

Λ(BaSO4)=Λ(BaCl2)+Λ(H2SO4)2Λ(HCl)

Λ(BaSO4)=280+8602×426

Λ(BaSO4)=288 S cm2 mol1

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