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Standard VII

Chemistry

Conductance of Electrolytic Solution

The molar con...

Question

The molar conductivity of $0.04 M$ solution of $M g C l_{2}$ is $200 S c m^{2} m o l^{- 1}$ at $298 K$ . A cell with electrodes that are $2.0 {cm}^{2}$ in surface area and $0.50 cm$ apart is filled with $M g C l_{2}$ solution.
Conductance of $M g C l_{2}$ solution is:
[1 Mark]

6 \times 10^{- 3} S

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32 S

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0.032 S

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None of these

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Solution

The correct option is C $0.032 S$
Given,
The concentration of the solution $(C) = 0.04 M$
Molar conductance $(Λ_{m}) = 200 S c m^{2} m o l^{- 1}$

$∴ Specific conductance (κ) = \frac{Λ_{m} \times C}{1000}$
$\Rightarrow κ = \frac{200 \times 0.04}{1000}$
$= 8 \times 10^{- 3} S c m^{- 1}$
Again, $Conductance = \frac{Specific conductance}{Cell constant}$
$= \frac{8 \times 10^{- 3}}{\frac{0.50}{2.0}} S = 0.032 S$

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The molar conductivity of 0.04 M solution of MgCl2 is 200Scm2mol−1 at 298 K. A cell with electrodes that are 2.0 cm2 in surface area and 0.50 cm apart is filled with MgCl2 solution. Conductance of MgCl2 solution is: [1 Mark]

The correct option is C 0.032 SGiven, The concentration of the solution (C)=0.04 M Molar conductance (Λm)=200Scm2mol−1 ∴Specific conductance (κ)=Λm×C1000 ⇒κ=200×0.041000 =8×10−3Scm−1 Again, Conductance=Specific conductanceCell constant =8×10−30.502.0 S=0.032 S

The molar conductivity of $0.04 M$ solution of $M g C l_{2}$ is $200 S c m^{2} m o l^{- 1}$ at $298 K$ . A cell with electrodes that are $2.0 {cm}^{2}$ in surface area and $0.50 cm$ apart is filled with $M g C l_{2}$ solution.
Conductance of $M g C l_{2}$ solution is:
[1 Mark]