Question

The molar conductivity of $0.04\text{M}$ solution of $MgC{l}_2$ is $200Sc{m}^{2}mo{l}^{-1}$ at $298\text{K}$. A cell with electrodes that are $2.0{\text{cm}}^2$ in surface area and $0.50\text{cm}$ apart is filled with $MgC{l}_2$ solution.
Specific conductance of $MgC{l}_2$ solution is:
[1 Mark]

• A. $8\times {10}^{-3}Sc{m}^{-1}$
• B. $5\times {10}^{-3}Sc{m}^{-1}$
• C. $0.03Sc{m}^{-1}$
• D. $0.08Sc{m}^{-1}$

Answer 1

The correct option is A $8\times {10}^{-3}Sc{m}^{-1}$

Given,
The concentration of the solution $\left(C\right)=0.04\text{M}$
Molar conductance $\left({\Lambda }_m\right)=200Sc{m}^{2}mo{l}^{-1}$

$\therefore \text{Specific conductance}\left(\kappa \right)=\frac{{\Lambda }_m\times C}{1000}$
$\Rightarrow \kappa =\frac{200\times 0.04}{1000}$
$=8\times {10}^{-3}Sc{m}^{-1}$