The molar conductivity of 0-05M BaCl2 solution at 25oC is 223-1cm2mol-1- What is its conductivity-

Λ m=K× 1000 M ⇒ K=( 223× 0.05 1000 #160; ) ⇒ K=( 11.15 1000 #160; ) =0.01115Ω #160; ^ 1 cm ^ 1 ...

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Conductance and Conductivity

The molar con...

Question

The molar conductivity of $0.05 M B a C l_{2}$ solution at $25^{o} C$ is $223 Ω^{- 1} c m^{2} m o l^{- 1}$ . What is its conductivity?

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Molar conductivity of a solution $1.26 \times 10^{2} Ω^{- 1} c m^{2} m o l^{- 1}$ , Its molarity is 0.01. its specific conductivity will be :

0.01 M A g N O_{3}

25^{o} C

1442 Ω

0.01 M A g N O_{3}

124.8 Ω^{- 1} c m^{2} m o l^{- 1}

0.20 m o l L^{- 1}

20^{0} C i s 2.48 \times 10^{- 4} o h m^{- 1} c m^{- 1}

7.5 \times 10^{- 3} M

K C l

25^{o} C

1005 o h m s

(o h m^{- 1} c m^{2} m o l^{- 1})

= 1.25 c m^{- 1}

25^{\circ} C

9.54 o h m^{- 1} c m^{2} m o l^{- 1}

238 o h m^{- 1} c m^{2} m o l^{- 1}

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