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Crystallisation

The molar con...

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The molar conductivity of acetic acid solution at infinite dilution is 390.7 . Calculate the moalr conductivity of 0.01M acetic acid solution, given that the dissociation of acetic acid is

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Q. The molar conductivity of acetic acid at infinite dilution is

390.7

0.1 M

acetic acid solution is

5.2 S c m^{2} m o l^{- 1}

. Degree of dissociation of acetic acid is X%, value of 3X is:

Q. The molar conductivity of acetic acid at infinite dilution is 390.7 and for 0.1 M acetic acid solution is 5.2 mho cm

^{2}

^{- 1}

. The degree of dissociation of 0.1 M

{CH}_{3} COOH

Q. The specific conductance of

0.01 M

solution of acetic acid was found to be

0.0163 S m^{- 1}

25 ° C

. Calculate the degree of dissociation of the acid. Molar conductance of acetic acid at infinite dilution is

390.7 \times 10^{- 4} S m^{2} m o l^{- 1}

25 ° C

.

25^{o} C

, the specific conductance of

0.01 M

aqueous solution of acetic acid is

1.63 \times 10^{- 2} S m^{- 1}

and the molar conductance at infinite dilution is

390.7 \times 10^{- 4} S m^{2} m o l^{- 1}

. Calculate the dissociation constant

(K_{a})

Q. The molar conductivity of acetic acid at infinite dilution is

387 S c m^{2} m o l^{- 1}

. At the same temperature,

0.001

M solution of acetic acid, molar conductivity is 55 S

c m^{2} m o l^{- 1}

α

is the degree of dissociation of

0.1

N acetic acid. What is the value of 600

α

1 - α = 1

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