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Question

The molar enthalpy change for H2O(1)H2O(g) at 373K and 1 atm is 41kJ/mol. Assuming ideal behavior, the internal energy change for vaporization of 1 mol of water at 373K and 1 atm in kJ mol1 is ?

A
30.2
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B
41.0
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C
48.1
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D
37.9
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Solution

The correct option is D 37.9

W=nRT=1(8.314×373)×103=3.10KJ
q=41KJ
ΔU=37.9KJ

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