The molar freezing point constant for water is 1-86- C mole -1- If 342 gm of canesugar C 12 H 22 O 11 are dissolved in 1000 gm of water- the solution will freeze atA- 1-86- CB- -3-92- CC- 2-42- CD- -1-86- C

The correct option is D 1.86°C ...

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Standard XII

Chemistry

Depression in Freezing Point

The molar fre...

Question

The molar freezing point constant for water is 1.86 °C mole^-1. If 342 gm of canesugar (C₁₂H₂₂O₁₁) are dissolved in 1000 gm of water, the solution will freeze at

-1.86°C

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1.86°C

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-3.92°C

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2.42°C

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Solution

The correct option is A
-1.86°C

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The molar freezing point constant for water is 1.86 °C mole-1. If 342 gm of canesugar (C12H22O11) are dissolved in 1000 gm of water, the solution will freeze at

The correct option is A -1.86°C

The molar freezing point constant for water is 1.86 °C mole^-1. If 342 gm of canesugar (C₁₂H₂₂O₁₁) are dissolved in 1000 gm of water, the solution will freeze at

The correct option is A
-1.86°C