The molar heat capacity ( Cp) of water at constant pressure is 75 JK−1mole−1. The increase in temperature (in K) of 100 g of water when 2kJ of heat is supplied to it is:
A
2.4 K
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B
3.6 K
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C
4.8 K
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D
5.2 K
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Solution
The correct option is C 4.8 K Given: molar heat capacity ( Cp) : 75 JK−1mole−1 = 7518JK−1g−1
mass of water = 100 g
We know, q=mCpΔT
where m = mass of the water
q = 2000 J
So, 2000 J = 100×7518ΔT
On calculating, ΔT = increase in temperature = 4.8 K