The correct option is A
103R
Given work done,
W=Q4
Where, Q is heat supplied,
As we know Molar heat capacity at constant volume,
CV=52R
Internal energy,
dU=CVdT
⇒dU=(52R)dT
⇒dT=2(dU)5R …(i)
From first law of thermodynamics,
dU=dQ−dW=Q−Q4
dU=3Q4
Now molar heat capacity,
C=dQdT=Q2(du)5R
Substituting the value of dU,
C=5RQ2(3Q4)
C=103R