The molar heat capacity of a monoatomic gas is:

4 / 2 R

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3 / 2 R

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5 / 2 R

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zero

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Solution

The correct option is A $3 / 2 R$
In a monoatomic gas, each atom has $3$ degrees o freedoms. They are of translation type. They contribute to the heat capacity.
$N$ atoms of a monoatomic gas has $3 N$ degrees of freedom.
Hence,
$C_{V} = (\frac{\partial U}{\partial T})$
$= \frac{3}{2} N K_{B}$
$= \frac{3}{2} n R$
The molar heat capacity is $\frac{C_{V, m}}{n} = 32 R$

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The molar heat capacity of a monoatomic gas is:

The correct option is A 3/2RIn a monoatomic gas, each atom has 3 degrees o freedoms. They are of translation type. They contribute to the heat capacity.N atoms of a monoatomic gas has 3N degrees of freedom. Hence, CV=(∂U∂T)=32NKB=32nRThe molar heat capacity is CV,mn=32R