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Standard XII

Chemistry

Molar and Specific Heat Capacity

The molar hea...

Question

The molar heat capacity of water at constant pressure, $C_{p}$ is 75 J $K^{- 1} m o l^{- 1}$ . When 10 KJ of heat is supplied to 1 kg water which is free to expand, the increase in temperature of water is:

2.4 K

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4.8 K

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3.2 K

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10 K

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Solution

The correct option is A 2.4 K
Given, Heat supplied to 1Kg of water, $Q = 10 k J = 10000 J$
Mass of water, $m = 1 k g = 1000 g = \frac{1000}{18 g / m o l} = 55.5 m o l$
Heat supplied to m gm of water, $Q = m C Δ t$
$Δ t = \frac{Q}{m C} = \frac{10000}{55.5 \times 75} = 2.4 K$

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The molar heat capacity of water at constant pressure, Cp is 75 J K−1mol−1. When 10 KJ of heat is supplied to 1 kg water which is free to expand, the increase in temperature of water is:

The correct option is A 2.4 KGiven, Heat supplied to 1Kg of water, Q=10 kJ=10000JMass of water, m=1kg=1000g=100018g/mol=55.5molHeat supplied to m gm of water, Q=mCΔtΔt=QmC=1000055.5×75=2.4 K

The molar heat capacity of water at constant pressure, $C_{p}$ is 75 J $K^{- 1} m o l^{- 1}$ . When 10 KJ of heat is supplied to 1 kg water which is free to expand, the increase in temperature of water is:

The correct option is A 2.4 K
Given, Heat supplied to 1Kg of water, $Q = 10 k J = 10000 J$
Mass of water, $m = 1 k g = 1000 g = \frac{1000}{18 g / m o l} = 55.5 m o l$
Heat supplied to m gm of water, $Q = m C Δ t$
$Δ t = \frac{Q}{m C} = \frac{10000}{55.5 \times 75} = 2.4 K$