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Crystal Field Split in Octahedral Complexes

The molar ion...

Question

The molar ionic conductances of the octahedral complexes.
( I ) $P t C l_{4} .5 N H_{3}$ ( II ) $P t C l_{4} .4 N H_{3}$ ( III ) $P t C l_{4} .3 N H_{3}$ ( IV ) $P t C l_{4} .2 N H_{3}$

I < I I < I I I < I V

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I V < I I I < I I < I

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I I I < I V < I I < I

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I V < I I I < I < I I

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Solution

The correct option is B $I V < I I I < I I < I$
In octahedral complexes, metal is coordinated with 6 ligands.
No. of ion given by complexes-
I - 4 ion (one complex ion + 3 chloride ion)
II - 3 ion (one complex ion + 2 chloride ion)
III - 2 ion (one complex ion + 1 chloride ion)
IV - no ion.
So molar conductance order is I > II > III > IV

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