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Standard XII

Chemistry

Atomic Number and Mass Number

The molar mas...

Question

The molar mass of $N_{2} O$ as well as $C O_{2}$ is $44 g m o l^{- 1}$ . At $25^{o} C$ and 1 atm pressure, 1 L $N_{2} O$ contains n molecules of gas. The number of $C O_{2}$ molecules in 2 L under same conditions will be:

n

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2 n

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\frac{n}{2}

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\frac{n}{4}

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Solution

The correct option is C $2 n$
We have,
$P V = n R T$
P, R, T are same, hence we get
$\frac{V_{1}}{V_{2}} = \frac{n_{1}}{n_{2}}$
n = $\frac{n o . o f m o l e c u l e s}{N_{A}}$ =number of moles
$\frac{1}{2} = \frac{n}{m o l e c u l e s o f C O_{2}}$
hence, the number of molecules of $C O_{2}$ $= 2 n$

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The molar mass of N2O as well as CO2 is 44gmol−1. At 25oC and 1 atm pressure, 1 L N2O contains n molecules of gas. The number of CO2 molecules in 2 L under same conditions will be:

The correct option is C 2nWe have,PV=nRTP, R, T are same, hence we getV1V2=n1n2n =no.ofmoleculesNA =number of moles 12=nmoleculesofCO2hence, the number of molecules of CO2 =2n

The molar mass of $N_{2} O$ as well as $C O_{2}$ is $44 g m o l^{- 1}$ . At $25^{o} C$ and 1 atm pressure, 1 L $N_{2} O$ contains n molecules of gas. The number of $C O_{2}$ molecules in 2 L under same conditions will be: