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Standard XII

Chemistry

Solubility Product

The molar sol...

Question

The molar solubility (in $m o l {l i t r e}^{- 1}$ ) of a sparingly soluble salt $M X_{4}$ is $S$ . The corresponding solubility product $K_{s p}$ is given by the relation:

S = {(K_{s p} / 128)}^{1 / 4}

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S = {(218 K_{s p})}^{1 / 4}

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S = {(256 K_{s p})}^{1 / 5}

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S = {(K_{s p} / 256)}^{1 / 5}

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Solution

The correct option is B $S = {(K_{s p} / 256)}^{1 / 5}$
$M X_{4} ⇌ M^{4 +} + 4 X^{-}$
$S$ $4 S$
$K_{s p} = [S] [4 S]^{4} = 256 S^{5}$
$S = (K_{s p} / 256)^{(1 / 5)}$

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Similar questions

The molar solubility ( $m o l L^{- 1})$ of a sparingly soluble salt $M X_{4}$ is $^{'} S^{'}$ . The corresponding solubility product is $K_{S P}$ . $^{'} S^{'}$ is given in terms of $K_{S P}$ by the relation

Q. The molar solubility in

(m o l L^{- 1})

of a sparingly soluble salt

M X_{4}

^{'} s^{'}

.The molar solubility product is

K_{s p}

^{'} s^{'}

is given in terms of

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by the relation:

Q. The molar solubility (in

m o l L^{- 1})

of a sparingly soluble salt

M X_{4}

^{'} S^{'}

. The corresponding solubility product is

^{'} K_{s p}^{'}

^{'} S^{'}

in term of

^{'} K_{s p}^{'}

is given by the relation:

Q. The molar solubility

(m o l l t^{- 1})

of a sparingly soluble salt

M X_{4}

is `s`. The corresponding solubility product is

K_{s p}

. Then `s`can be given in terms of

k_{s p}

by the relation :

Q. The molar solubility (in mol

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of a sparingly soluble salt

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The molar solubility (in mol litre−1) of a sparingly soluble salt MX4 is S. The corresponding solubility product Ksp is given by the relation:

The correct option is B S=(Ksp/256)1/5MX4⇌M4++4X− S 4SKsp=[S][4S]4=256S5S=(Ksp/256)(1/5)

The molar solubility (in $m o l {l i t r e}^{- 1}$ ) of a sparingly soluble salt $M X_{4}$ is $S$ . The corresponding solubility product $K_{s p}$ is given by the relation:

The correct option is B $S = {(K_{s p} / 256)}^{1 / 5}$
$M X_{4} ⇌ M^{4 +} + 4 X^{-}$
$S$ $4 S$
$K_{s p} = [S] [4 S]^{4} = 256 S^{5}$
$S = (K_{s p} / 256)^{(1 / 5)}$