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Byju's Answer

Standard XII

Chemistry

Conductance of Electrolytic Solution

The molar sol...

Question

The molar solubility ( $m o l L^{- 1})$ of a sparingly soluble salt $M X_{4}$ is $^{'} S^{'}$ . The corresponding solubility product is $K_{S P}$ . $^{'} S^{'}$ is given in terms of $K_{S P}$ by the relation

S = (256K_SP)^1/5

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S = (128K_SP)^1/4

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S = (K_SP/128)^1/4

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S = (K_SP/256)^1/5

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Solution

The correct option is D
S = (K_SP/256)^1/5

$M X_{4}$ $\to$ $M + 4 X$
s 4s

$K_{S P}$ = $(4 s)^{4} s$

$K_{S P}$ = $256 s^{5}$

$S = {(\frac{K_{S P}}{256})}^{\frac{1}{5}}$

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Similar questions

Q. The molar solubility in

(m o l L^{- 1})

of a sparingly soluble salt

M X_{4}

^{'} s^{'}

.The molar solubility product is

K_{s p}

^{'} s^{'}

is given in terms of

K_{s p}

by the relation:

Q. The molar solubility (in

m o l L^{- 1})

of a sparingly soluble salt

M X_{4}

^{'} S^{'}

. The corresponding solubility product is

^{'} K_{s p}^{'}

^{'} S^{'}

in term of

^{'} K_{s p}^{'}

is given by the relation:

Q. If the molar solubility

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A B_{3}

s

. The corresponding solubility product is

K_{s p}

. The solubility

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can be written in terms of

K_{s p}

by the relation:

Q. The molar solubility

(m o l l t^{- 1})

of a sparingly soluble salt

M X_{4}

is `s`. The corresponding solubility product is

K_{s p}

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by the relation :

Q. The molar solubility (in mol

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The molar solubility (molL−1) of a sparingly soluble salt MX4 is ′S′. The corresponding solubility product is KSP . ′S′ is given in terms of KSP by the relation

The correct option is D S = (KSP/256)1/5 MX4 → M+4X s 4s KSP = (4s)4s KSP = 256s5 S = (KSP256)15

The molar solubility ( $m o l L^{- 1})$ of a sparingly soluble salt $M X_{4}$ is $^{'} S^{'}$ . The corresponding solubility product is $K_{S P}$ . $^{'} S^{'}$ is given in terms of $K_{S P}$ by the relation

The correct option is D
S = (K_SP/256)^1/5

$M X_{4}$ $\to$ $M + 4 X$
s 4s

$K_{S P}$ = $(4 s)^{4} s$

$K_{S P}$ = $256 s^{5}$

$S = {(\frac{K_{S P}}{256})}^{\frac{1}{5}}$