The molar specific heat of oxygen at constant pressure Cp=7.03cal/mol∘C and R=8.31J/mol∘C. The amount of heat taken by 5mol of oxygen when heated at constant volume from 10∘C to 20∘C will be approximately
A
25cal
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B
50cal
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C
250cal
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D
500cal
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Solution
The correct option is C250cal The value of R in caloric system is 2 Thus, using Cv=Cp−R
Thus, Cv=7.03−2 So,
Cv=5.03
Now, amount of heat required will be Q = U = nCvΔT Q = 5×5.03×10 Q≈250cal