wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The molar volume of KCl and NaCl are 37.46 ml and 27.94 ml. The ratio of unit cell edges of the two crystals is :

A
1.296
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.116
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.341
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.950
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1.116
Molar volume =NA×43πr3 where NA is Avogadro number,
Now Molar volume of KCl is 37.46cm3 So NA×43πR3=37.46 cm3
6.022×1023×43πR3=37.46 cm3
On solving this gives R=2.458×108 cm
And for NaCl by using the same formula it gives R=2.22×108 cm
Now the ratio of edge length must be equal to ratio of radii as both belong to same crystal system so KClNaCl=2.4582.22=1.108

flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Crystal System and Bravais Lattice
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon