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Mole Concept

The molarity ...

Question

The molarity $(M)$ of $K M n O_{4}$ solution in basic medium is :

0.8 M

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0.08 M

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0.26 M

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0.026 M

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Solution

The correct option is A $0.8 M$
$M n O_{4}^{⊝} (b a s i c) \equiv S_{2} O_{3}^{2 -} (S_{2} O_{3}^{2 -} \to 2 S O_{4}^{2 -} + 8 e^{-}) (n = 8)$
$n$ factor $= 1$ $n$ factor $= 8$
In basic medium, Mn(VII) is reduced to Mn(VI), n=1
$100 m L \times N \equiv 100 m L \times 0.1 \times 8$
$N = 0.8$
$M = \frac{N}{n f a c t o r} = 0.8 M$

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