Question

The molarity of $98$ percent $H_{2}S{O}_4$ (density $=1.8g/ml$) by weight would be:

• A. $1M$
• B. $36M$
• C. $9M$
• D. $18M$

Answer 1

The correct option is D $18M$

$98$% d= $1.8g/ml=x$

Molar mass of $H_{2}S{O}_4=98g$

Molarity= $\frac{10\times x\times d}{\text{Molar mass}}=\frac{10\times 98\times 1.8}{98}=10\times 1.8$

Molarity= $18M=18mol{L}^{-1}$