Question

The molarity of a 0.2 N $N{a}_{2}C{O}_3$ solution will be :

• A. 0.05 M
• B. 0.2 M
• C. 0.1 M
• D. 0.4 M

Answer 1

The correct option is C 0.1 M

n-factor far Na${}_{2}C{O}_3$ =2

$\because$ The n-factor of such salts is defined as the number of moles of electrons exchanged (lost or gained) by one mole of the salt. And there is the exchange of 2 electrons so its n factor is 2

Therefore, Normality = n-fator $\times$ molarity

Molarity =$\frac{0.2}{2}$ =0.1 M

Hence, the correct option is $C$