The molarity of a 19.6% (w/w) solution of sulphuric acid is:
(density of the solution is 1.020gcm−3 ; atomic mass: H = 1 amu, O = 16 amu and S = 32 amu)
A
2 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.5 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.5 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 2 M Given : Mass of sulphuric acid = 19.6 g Mass of the solvent = 80.4 g Density of the solution = 1.020 gcm−3 Molarity = moles of sulphuric acidvolume of the solution Number of moles of sulphuric acid=19.698=0.2 Volume of the solution=mass of the solutiondensity of the solution = 1001.020≈98cm−3 Molarity = 0.20.098 = 2.04 M