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Osmotic Pressure

The molarity ...

Question

The molarity of a 19.6% (w/w) solution of sulphuric acid is:

(density of the solution is $1.020 g c m^{- 3}$ ; atomic mass: H = 1 amu, O = 16 amu and S = 32 amu)

2 M

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3 M

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3.5 M

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2.5 M

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Solution

The correct option is A 2 M
Given :
Mass of sulphuric acid = 19.6 g
Mass of the solvent = 80.4 g
Density of the solution = 1.020 $g c m^{- 3}$
Molarity = $\frac{moles of sulphuric acid}{volume of the solution}$
$Number of moles of sulphuric acid = \frac{19.6}{98} = 0.2$
$Volume of the solution = \frac{mass of the solution}{density of the solution}$ = $\frac{100}{1.020}$ $\approx 98 c m^{- 3}$
Molarity = $\frac{0.2}{0.098}$ = 2.04 M

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The molarity of a 19.6% (w/w) solution of sulphuric acid is: (density of the solution is 1.020 g cm−3 ; atomic mass: H = 1 amu, O = 16 amu and S = 32 amu)

The molarity of a 19.6% (w/w) solution of sulphuric acid is:

(density of the solution is $1.020 g c m^{- 3}$ ; atomic mass: H = 1 amu, O = 16 amu and S = 32 amu)