Question

The molarity of a $9.8\%$ (w/w) of $H_{2}S{O}_4$ is:

[d = 1.2 g/mL]

• A. $1$ M
• B. $0.55$ M
• C. $0.1$ M
• D. $1.2$ M

Answer 1

Answer: (D)

$1.2$ M

9.8% (w/w) of $H_{2}S{O}_4$ solution means 9.8 g of solute in 100 g of solution.

Density of $H_{2}S{O}_4=1.2g/ml$

The volume of the solution $=\frac{Mass}{Density}=\frac{100}{1.2}=83.33ml$

Molarity $=\frac{9.8\times 1000}{98\times 83.33}=1.2M$