The molarity of a glucose solution containing 36 g of glucose per 400 mL of the solution is:
A
1.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.05
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D0.5 Molarity is a measure of the concentration of a solute in a solution or of any chemical species, in terms of amount of a substance in a given volume. A commonly used unit for molar concentration used in chemistry is mol/L. A solution of concentration 1 mol/L is also denoted as 1 molar (1 M).
Molar concentration or molarity is most commonly expressed in units of moles of solute per litre of solution. For use in broader applications, it is defined as amount of solute per unit volume of solution, or per unit volume available for the species, represented by lowercase c:
c=nV
where,
n= no. of moles of solute.
V= volume of solution in liters.
Calculation:
Number of moles of glucose is n=36180=0.2 moles
The volume of solution in liters is V=4001000=0.4 litres