The molarity of a solution in which $5.3$ g $N a_{2} C O_{3}$ is dissolved in $500$ mL will be:

1.0

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0.1

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0.20

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0.2

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Solution

The correct option is B $0.1$ M
Molecular mass of $N a_{2} C O_{3} = 106 g m o l^{- 1}$
$∴$ Number of moles $= \frac{53}{106} = 0.05$ mol
As $0.05$ mol are dissolved in $500$ mL;
Number of moles dissolved in $1000$ mL ( $1$ L) or molarity of th solution
$= \frac{0.05}{500} \times 1000 = 0.1$ M.

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