The molarity of a solution $M_{3}$ obtained by mixing these two solutions:
1. $750 m L$ of $0.5 M H C l$
2 $250 m L$ of $2 M H C l$
will be:

1.75 M

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0.975 M

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0.875 M

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1.00 M

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Solution

The correct option is C $0.875 M$
$Millimole of solution I = M_{1} \times V_{1} = 750 \times 0.5 = 375 m m o l$
$Millimole of solution II = M_{2} \times V_{2} = 250 \times 2 = 500 m m o l$

$Total volume = V_{1} + V_{2} = 1000 m L$
$∴ M_{3} = \frac{M_{1} \times V_{1} + M_{2} \times V_{2}}{V_{1} + V_{2}} M_{3} = \frac{375 + 500}{1000} = 0.875 M$

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