The molarity of a solution obtained by mixing 750 mL of 0.5M HCl with 250 mL of 2M HCl will be:
(IIT-JEE-2013)

1.00 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.75 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.975 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.875 M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.875 M
$M_{1} V_{1} + M_{2} V_{2} = M V$
$M = \frac{M_{1} V_{1} + M_{1} V_{2}}{V} = \frac{0.5 \times 750 + 2 \times 250}{1000}$
M = 0.875

Suggest Corrections

Similar questions

250 m l

0.5 M H C l

750 m l

2 M H C l

The molarity of a solution obtained by mixing 750 mL of 0.5 M HCL with 250 mL of 2 M HCL will be

H_{2} O

H C l

Join BYJU'S Learning Program