The molarity of an aqueous solution of glycol is 12 M. The density of the solution is 1.392 g/mL. Find the mole fraction of glycol.
(Given, molar mass of glycol =62 g/mol)
A
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B0.25 Given:
Molarity of the solution =12M
Assuming 1 L of the solution,
Moles of ethylene glycol =12mol
Molar mass of ethylene glycol =62g/mol (given)
Mass of ethylene glycol =62×12=744g
Volume of the solution =1 L
Density of the solution =1.392 g/mL (given)
Mass of the solution =1000×1.392=1392g
Mass of water =(1392−744)g=648 g
Moles of water =64818=36mol
Total moles of ethylene glycol and water =36+12=48mol
Mole fraction og glycol =1248=0.25