Question

The molarity of $H_{2}S{O}_4$ solution, which has a density $1.84g/cc$. at ${35}^{\circ }C$ and contains $98$% by weight is:

• A. $1.84M$
• B. $18.4M$
• C. $20.6M$
• D. $24.5M$

Answer 1

Answer: (B)

$18.4M$

$100gm$ solution contains $98gm{H}_{2}S{O}_4$.

$\frac{100}{1.84}c{m}^3$ contains $98gmof{H}_{2}S{O}_4$.

$1000c{m}^3$ solution contains

$=\frac{98}{100}\times 1.84\times 1000gm{H}_{2}S{O}_4$

$=\frac{98}{100}\times \frac{1.84\times 1000}{98}$ moles of $H_{2}S{O}_4$

$=18.4M$.

Hence, the correct option is $B$.