Question

The molarity of the solution containing $2.8\%$ (mass/volume) solution of KOH is : (Given atomic mass K=39) is :

• A. 0.1 M
• B. 0.05 M
• C. 0.2 M
• D. 1 M

Answer 1

The correct option is B 0.05 M

Given that, $2.8\%\left(m/v\right)$

$m=\frac{n}{v}=\frac{2.8}{\frac{56.1056}{1}}$

$=0.049$

$=0.05M$