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Mole Concept

The mole frac...

Question

The mole fraction of a given sample of $I_{2}$ in $C_{6} H_{6}$ is 0.2 . The molality of $I_{2}$ in $C_{6} H_{6}$ is:

0.32

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3.2

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0.032

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0.48

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Solution

The correct option is B $3.2$
$I_{2} \to s o l u t e (A)$
$C_{6} H_{6} \to s o l v e n t (B)$

As we already know,

$m = \frac{X_{A} \times 1000}{(1 - X_{A}) m_{B}}$

where $m_{B} a n d X_{A}$ are the molecular weight of solvent and mole fraction of solute respectively.

$m = \frac{0 \cdot 2 \times 1000}{(1 - 0 \cdot 2) 78}$

$= 3 \cdot 2 \times 10^{- 3} \times 1000$

$= 3 \cdot 2$

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