Question

The mole fraction of a solute in a solution of n-heptane is $0.25$. The molality of the solution will be:
[Report the answer upto two decimal place]

Answer 1

mole fraction of solute, $x_A=0.25$
mole fraction of solvant, $x_B=0.75$
molar mass of $C_7{H}_{16}=100\text{g/mol}$
$\text{Molality}=\frac{x_A\times 1000}{x_B\times 100}$
$=\frac{0.25\times 1000}{0.75\times 100}=3.33$