The correct option is B Molality of the solution is 3.33 m
Assuming, total moles of the solution =1 mol
so, moles of acetone =0.25 mol
molar mass of acetone =58 g/mol
therefore, mass of acetone =14.5 g
moles of heptane =0.75 mol
molar mass of heptane (C7H16) =100 g/mol
therefore, mass of heptane =75 g
Total mass of the solution =89.5 g
volume of the solution = massdensity=89.50.895=100 mL
Molarity of the solution= moles of solutevolume of the solution(L)=0.250.1=2.5 M
mass of solvent (heptane) =89.5−14.5=75 g
Molality of the solution= moles of solutemass of the solvent (kg)=0.250.075=3.33 m