The mole fraction of component A in the vapour phase is χ1 and mole fraction of component A in liquid mixture is χ2 (PoA = vapour pressure of pure A; PoB = vapour pressure of pure B). Then the total vapour pressure of the liquid mixture is:
A
PoAχ2χ1
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B
PoAχ1χ2
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C
PoBχ1χ2
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D
PoBχ2χ1
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Solution
The correct option is APoAχ2χ1
ANS: - Mole fraction of component A in vapor phase - x1
In Liquid Phase x2
Vapor Pressure of pure A=P∘A
Vaporer pressure of pure B=P∘B
Mole fraction of component A in the vapor phase is given by