The mole fraction of NaClin water is 0.22. What is its mass percent ?

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Solution

$M a s s f r a c t i o n a n d m o l e f r a c t i o n a r e r e l a t e d a s M a s s % = (X_{S o l u t e} \times \frac{M_{S o l u t e}}{M_{S o l u t e} + M_{S o l v e n t}}) \times 100 X_{s o l u t e} = 0.22 M_{S o l u t e} = M_{N a C l} = 58.5 M_{s o l v e n t} = M_{H_{2} O} = 18 M a s s % = (0.22 \times [\frac{58.5}{58.5 + 18}]) \times 100 = 0.17 \times 100 = 17 %$

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The mole fraction of NaClin water is 0.22. What is its mass percent ?

Mass fraction and mole fraction are related asMass % = XSolute × MSolute MSolute + MSolvent × 100Xsolute = 0.22MSolute = MNaCl = 58.5Msolvent = MH2O = 18 Mass % = 0.22 × 58.558.5 + 18 × 100 = 0.17 × 100 = 17 %