The mole fraction of the solute in one molal aqueous solution is:

0.027

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.036

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.018

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.009

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.018
Molality= $\frac{N u m b e r o f m o l e s o f s o l u t e}{M a s s o f s o l v e n t i n k g}$
1 mole of solute corresponds to 1 kg of solvent
Moles of solvent = $\frac{m a s s o f s o l v e n t i n g r a m}{m o l a r m a s s o f s o l v e n t}$
= $\frac{1000}{18}$
Mole fraction of solute= $\frac{m o l e s o f s o l u t e}{t o t a l m o l e s}$
Total moles= 1+ $\frac{1000}{18}$ = $\frac{1000}{18}$
Mole fraction of solute= $\frac{18}{1000}$

=0.018

Suggest Corrections