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Stoichiometry

The mole frac...

Question

The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene $(P_{B}^{o} = 120 t o r r)$ and toluene $(P_{T}^{o} = 80 t o r r)$ having 2.0 mol of each is,

A

0.5

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B

0.25

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C

0.6

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D

0.4

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Solution

The correct option is D 0.4

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Similar questions

Q. Mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene

(p^{\circ} = 120 ton)

(p^{\circ} = 80 ton)

having 3 mole of each is:

Q. Vapour pressure of pure benzene is 119 torr and of toluene is 37.0 torr at the same temperature mole fraction of toluene in vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50, will be:

Q. Vapour pressure of pure benzene is

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at the same temperature. Then mole fraction of toluene in vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene

0.50,

Q. Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is

x

x \times 10^{- 3}

)(rounding off to 3 digits)

Q. Calculate the mole fraction of toluene in the vapor phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of 0.5 (The vapor pressure of pure Benzene is 119 torr and that of toluene is 37 torr at the same temperature:

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