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Byju's Answer
Standard XII
Chemistry
Compressibility Factor
The mole frac...
Question
The mole fraction of urea in an aqueous urea solution containing
900
g
of water is
0.05
. If the density of solution is
1.2
g
c
m
−
3
, the molarity of urea solution is
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Solution
Let moles of urea
=
x
∴
x
x
+
900
18
=
0.05
⇒
x
=
50
19
Mass of solution
=
50
19
×
60
+
900
=
20100
19
Volume of solution
=
20100
19
×
1.2
m
l
=
20.1
19
×
1.2
L
Molarity
=
50
19
20.1
19
×
1.2
=
50
×
1.2
20.1
=
60
20.1
≅
2.985
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