The mole fraction of water in 20% aqueous hydrogen peroxide solution is:

0.2

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0.8

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0.883

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0.117

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Solution

The correct option is C $0.883$
$\Rightarrow M . ω t o f H_{2} O_{2} = 34$

20 % aqueous $H_{2} O_{2}$ solution means $20 g m H_{2} O_{2}$ in $100 g m s o l u t i o n$ .

So, mass of water $= 100 - 20 = 80 g m$
Mole fraction of water $X_{w a t e r} = \frac{n_{w a t e r}}{n_{w a t e r} + n_{H_{2} O_{2}}}$ $= \frac{\frac{80}{18}}{\frac{80}{18} + \frac{20}{34}}$ $= 0.883$

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The mole fraction of water in 20% aqueous hydrogen peroxide solution is:

The correct option is C 0.883⇒M.ωt of H2O2=3420 % aqueous H2O2 solution means 20gm H2O2 in 100 gm solution.So, mass of water =100−20=80gmMole fraction of water Xwater=nwaternwater+nH2O2=80188018+2034=0.883