The mole fraction of water in $20 %$ aqueous solution of $H_{2} O_{2}$ is

\frac{77}{68}

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\frac{68}{77}

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\frac{20}{80}

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\frac{80}{20}

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Solution

The correct option is B $\frac{68}{77}$
Mole fraction of water = 80/18+20/34.
= 68/77.
hence,, 68/77 is the mole fraction of water in 20% aqueous solution of h2o2.

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