The mole ratio between the number of molecules in $2 g$ of Hydrogen $(H_{2})$ and $32 g$ of Oxygen $(O_{2})$ is __________

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Solution

Moles is calculated from the ratio of the mass of the compound and the molar weight of the compound.
We will calculate the moles of Hydrogen $(H_{2})$
$m o l e s o f H y d r o g e n (H_{2}) = \frac{m a s s}{m o l a r m a s s} m o l e s o f H y d r o g e n (H_{2}) = \frac{2 g}{2 \frac{g}{m o l}} m o l e s o f H y d r o g e n (H_{2}) = 1 m o l$
We will calculate the moles of Oxygen $(O_{2})$
$m o l e s o f O x y g e n (O_{2}) = \frac{m a s s}{m o l a r m a s s} m o l e s o f O x y g e n (O_{2}) = \frac{32 g}{32 \frac{g}{m o l}} m o l e s o f O x y g e n (O_{2}) = 1 m o l$
The mole ratio will be $1 m o l : 1 m o l = 1 : 1$
So, the mole ratio between the number of molecules in $2 g$ of Hydrogen $(H_{2})$ and $32 g$ of Oxygen $(O_{2})$ is $1 : 1$

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The mole ratio between the number of molecules in 2gof Hydrogen (H2) and 32g of Oxygen O2is __________

The mole ratio between the number of molecules in $2 g$ of Hydrogen $(H_{2})$ and $32 g$ of Oxygen $(O_{2})$ is __________