Question

The mole $\left(s\right)$ off $KCI{O}_3$ which on decomposition give just sufficient $O_2$ to convert $2$ mole of aluminium to its oxide, is/are ?

• A. $1.5$
• B. $2.5$
• C. $1$
• D. $1.33$

Answer 1

The correct option is C $1$

$2KCl{O}_3⟶2KCl+3O_2$

$2$ moles of $KCl{O}_3$ give $3$ moles of $O_2$.

$4Al+3O_2⟶2A{l}_2{O}_3$

$4$ moles of $Al$ require $3$ moles of $O_2$.

$\therefore 2$ moles of $Al$ require $1.5$ mole of $O_2$.

$\therefore 1.5$ mol $O_2$ will be given by $\frac{2}{2}=1$ mol of $KCl{O}_3$.