The molecular formula of a commercial resin used for exchanging ions in water softening is $C_{8} H_{7} S O_{3}^{-} N a^{+}$ $(M o l e c u l a r w e i g h t = 206)$ . The maximum uptake of $C a^{2 +}$ ions by the resin when expressed in mole per gram resin was found to be $\frac{1}{x}$ . Find the value of $x$ .

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Solution

2 mole of water softner is required for1 mole of $C a^{2 +}$ ion
So, 1 mole of water softner is required $\frac{1}{2}$ mole of $C a^{2 +}$ ion
Thus, $\frac{1}{2 \times 206} = \frac{1}{412} m o l / g$ will be maximum uptake.
Hence,
$x = 412$

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The molecular formula of a commercial resin used for exchanging ions in water softening is $C_{8} H_{7} S O_{3} N a$ (molecular weight = 206). What would be the maximum uptake of $C a^{2 +}$ ions by the resin when expressed in mole per gram resin?

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The molecular formula of a commercial resin used for exchanging ions in water softening is C8H7SO−3Na+ (Molecular weight=206). The maximum uptake of Ca2+ ions by the resin when expressed in mole per gram resin was found to be 1x. Find the value of x.

2 mole of water softner is required for1 mole of Ca2+ ion So, 1 mole of water softner is required 12 mole of Ca2+ ion Thus, 12×206=1412 mol/g will be maximum uptake. Hence, x=412

2 mole of water softner is required for1 mole of $C a^{2 +}$ ion
So, 1 mole of water softner is required $\frac{1}{2}$ mole of $C a^{2 +}$ ion
Thus, $\frac{1}{2 \times 206} = \frac{1}{412} m o l / g$ will be maximum uptake.
Hence,
$x = 412$