The molecular formula of Mercury (II) chloride is:

H g C l

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H g_{2} C l_{2}

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H g C l_{3}

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H g C l_{2}

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Solution

The correct option is D $H g C l_{2}$
$(I I)$ resembles the oxidation state of Mercury. Oxidation state of mercury is $+ 2$ and that of chlorine is $- 1$ . Hence, it will be $H g C l_{2}$

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Similar questions

Q. The equilibrium constant for the disproportionation of

H g C l_{2}

into

H g C l^{+}

and

H g C l_{3}^{-}

is ...............
Given,

H g C l^{+} + C l^{-} ⇌ H g C l_{2}; K_{1} = 3 \times 10^{6}

H g C l_{2} + C l^{-} ⇌ H g C l_{3}^{-}; K_{2} = 9.0

Q. Given the equilibrium constants

H g C l^{\oplus} + C l^{⊖} \to H g C l_{2}, K_{1} = 3 \times 10^{6}

H g C l_{2} + C l^{⊖} \to H g C l_{3}^{⊖}, K_{2} = 8.9

The equilibrium constant for the disproportionation equilibrium

2 H g C l_{2} \to H g C l^{\oplus} + H g C l_{3}^{⊖}

is :

Q. Write the molecular formulae for the following compounds: Mercury (II) chloride.

Which of the following metal chloride gives white ppt and black ppt respectively with aequeous solution of gas (B)

A metal gives two chlorides ‘A’ and ‘B’. ‘A’ gives black precipitate with $N H_{4} O H$ and ‘B’ gives white. With KI ‘B’ gives a red precipitate soluble in excess of $K I$ . ‘A’ and ‘B’ are respectively :

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The molecular formula of Mercury (II) chloride is:

The correct option is D HgCl2(II) resembles the oxidation state of Mercury. Oxidation state of mercury is +2 and that of chlorine is −1. Hence, it will be HgCl2

The correct option is D $H g C l_{2}$
$(I I)$ resembles the oxidation state of Mercury. Oxidation state of mercury is $+ 2$ and that of chlorine is $- 1$ . Hence, it will be $H g C l_{2}$