The molecular formula of organic compound $X$ is $C_{5} H_{12} O$ . The possible number of position isomers of $X$ are:

4

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3

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2

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7

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Solution

The correct option is B $3$
Positional isomers are constitutional isomers that have the same carbon skeleton and the same functional groups but differ from each other in the location of the functional groups on or in the carbon chain. $C_{5} H_{12} O$ is formula of $P e n t a n o l$ . It may have 3 positional isomers.
$1 - p e n t a n o l, C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - O H$
$2 - p e n t a n o l, C H_{3} - C H_{2} - C H_{2} - C H - (O H) - C H_{3}$
$3 - p e n t a n o l, C H_{3} - C H_{2} - C H (O H) - C H_{2} - C H_{3}$

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