The molecular mass of an organic compound is $78$ and its percentage composition is $92.4 %$ $C$ and $7.6 % H$ . Determine the molecular formula of the compound.

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Solution

Carbon = $92.4$ grams
Hydrogen = $7.6$ grams
moles of Carbon = $\frac{12.4}{12} = 7.7$ moles
Moles of Hydrogen = $\frac{7.6}{1} = 7.6$ moles
Ratio = $\frac{7.7}{7.6} = 1$ (approx)
Empirical formula = $C H$
Molar mass = $78$
$n = 78 / C H (13) = 6$
molecular formula = $C_{6} H_{6}$

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The molecular mass of an organic compound is 78 and its percentage composition is 92.4% C and 7.6% H. Determine the molecular formula of the compound.

Carbon = 92.4 gramsHydrogen = 7.6 gramsmoles of Carbon = 12.412=7.7 molesMoles of Hydrogen =7.61=7.6 molesRatio = 7.77.6=1 (approx)Empirical formula = CHMolar mass = 78n=78/CH(13)=6molecular formula = C6H6

The molecular mass of an organic compound is $78$ and its percentage composition is $92.4 %$ $C$ and $7.6 % H$ . Determine the molecular formula of the compound.

Carbon = $92.4$ grams
Hydrogen = $7.6$ grams
moles of Carbon = $\frac{12.4}{12} = 7.7$ moles
Moles of Hydrogen = $\frac{7.6}{1} = 7.6$ moles
Ratio = $\frac{7.7}{7.6} = 1$ (approx)
Empirical formula = $C H$
Molar mass = $78$
$n = 78 / C H (13) = 6$
molecular formula = $C_{6} H_{6}$