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Standard XII

Chemistry

Empirical & Molecular Formula

The molecular...

Question

The molecular mass of butyric acid was determined by experiment to be 88 $g m o l^{- 1}$ . What is the molecular formula?
Empirical formula=. $C_{2} H_{4} O$

C_{4} H_{8} O_{2}

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C_{2} H_{4} O

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C H_{4} O

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C_{2} H_{4} O_{2}

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Solution

The correct option is A $C_{4} H_{8} O_{2}$
Empirical formula mass $= 44$
Molecular mass $= 88$
we know,
$\frac{Molecular mass}{Empirical mass} = \frac{88}{44} = 2$
$∴ Molecular formula =Empirical formula \times n = C_{4} H_{8} O_{2}$

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Butyric acid contains only C,H,O. A 4.24mg sample of butyric acid is completely burnt. It gives 8.45mg of CO2 and 3.46mg of H2O. What is the mass percentage of each element in butyric acid? The molecular mass of butyric acid was determined by experiment to be 88 a.m.u. What is the molecular formula?

Please help me solve this question briefly!!!

The empirical formula and molecular mass of a compound are $C H_{2} O$ and 180 g respectively. What will be the molecular formula of the compound ?

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Empirical & Molecular Formula

Standard XII Chemistry

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The molecular mass of butyric acid was determined by experiment to be 88 gmol−1. What is the molecular formula? Empirical formula=.C2H4O

The correct option is A C4H8O2Empirical formula mass =44 Molecular mass =88 we know, Molecular massEmpirical mass=8844=2 ∴Molecular formula =Empirical formula× n=C4H8O2

The molecular mass of butyric acid was determined by experiment to be 88 $g m o l^{- 1}$ . What is the molecular formula?
Empirical formula=. $C_{2} H_{4} O$

The correct option is A $C_{4} H_{8} O_{2}$
Empirical formula mass $= 44$
Molecular mass $= 88$
we know,
$\frac{Molecular mass}{Empirical mass} = \frac{88}{44} = 2$
$∴ Molecular formula =Empirical formula \times n = C_{4} H_{8} O_{2}$