The molecular mass of $C u S O_{4} .5 H_{2} O$ is:
(Atomic mass of $C u$ $=$ 63.5, $H$ $=$ 1, $O$ $=$ 16, $S$ $=$ 32)

233.5 gm/mole

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249.5 gm/mole

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251.5 gm/mole

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247.5 gm/mole

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Solution

The correct option is B 249.5 gm/mole
Molecular mass of a compound is the sum of atomic masses of each element present in the molecule.
Molecular mass $=$ atomic mass of $C u$ + atomic mass of $S$ + (9 $\times$ atomic mass of $O$ ) + (10 $\times$ atomic mass of $H$ ) $= 63.5 + 32 + 9 \times 16 + 10 \times 1 = 249.5 g m / m o l e$

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The molecular mass of CuSO4.5H2O is:(Atomic mass of Cu = 63.5, H = 1, O = 16, S = 32)

The correct option is B 249.5 gm/moleMolecular mass of a compound is the sum of atomic masses of each element present in the molecule. Molecular mass = atomic mass of Cu + atomic mass of S + (9 × atomic mass of O) + (10 × atomic mass of H) =63.5+32+9×16+10×1=249.5 gm/mole

The molecular mass of $C u S O_{4} .5 H_{2} O$ is:
(Atomic mass of $C u$ $=$ 63.5, $H$ $=$ 1, $O$ $=$ 16, $S$ $=$ 32)