The molecular mass of $K M n O_{4}$ is $M$ . Its equivalent mass in acidic medium will be

M

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M / 2

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M / 5

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M / 4

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Solution

The correct option is B $M / 5$
The molecular mass of $K m n O_{4}$ is M and the number of equivalents is 5 that is the number of electrons lost from $K m n O_{4}$ is 5.
So the equivalent weight of $K m n O_{4}$ is M/5.
Hence option C is correct.

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