Question

The molecular mass of $KMn{O}_4$ is $M$. Its equivalent mass in acidic medium will be

• A. $M$
• B. $M/2$
• C. $M/5$
• D. $M/4$

Answer 1

Answer: (C)

$M/5$

The molecular mass of $Kmn{O}_4$ is M and the number of equivalents is 5 that is the number of electrons lost from $Kmn{O}_4$ is 5.
So the equivalent weight of $Kmn{O}_4$ is M/5.
Hence option C is correct.